J^2-23J+22=0

Solution for J^2-23J+22=0 equation:

Simplifying
J2 + -23J + 22 = 0

Reorder the terms:
22 + -23J + J2 = 0

Solving
22 + -23J + J2 = 0

Solving for variable 'J'.

Factor a trinomial.
(1 + -1J)(22 + -1J) = 0

Subproblem 1
Set the factor '(1 + -1J)' equal to zero and attempt to solve:

Simplifying
1 + -1J = 0

Solving
1 + -1J = 0

Move all terms containing J to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1J = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1J = 0 + -1
-1J = 0 + -1

Combine like terms: 0 + -1 = -1
-1J = -1

Divide each side by '-1'.
J = 1

Simplifying
J = 1
Subproblem 2
Set the factor '(22 + -1J)' equal to zero and attempt to solve:

Simplifying
22 + -1J = 0

Solving
22 + -1J = 0

Move all terms containing J to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + -22 + -1J = 0 + -22

Combine like terms: 22 + -22 = 0
0 + -1J = 0 + -22
-1J = 0 + -22

Combine like terms: 0 + -22 = -22
-1J = -22

Divide each side by '-1'.
J = 22

Simplifying
J = 22
Solution
J = {1, 22}